两端接的电容都是一样,但是xtal_out端的振幅是xtal_in端的10倍。- i | d, }# c
表示此時放大器閉環增益有10倍,可以加大Cin以加大xtal_in端振幅,一般都是求out端的振幅及頻率穩定,: w# k4 P( L' O7 T
何必在意out/in的振幅大小呢?放大器開環增益以及晶体本身的損失與阻抗均非定值。
两端接的电容都是一样,但是xtal_out端的振幅是xtal_in端的10倍。& r, C6 b I% a7 x7 j. z
表示此時放大器閉環增益有10倍,可以加大Ci ... ( e0 J' c% A$ R) Ryeutay 發表於 2011-3-7 06:47 PM
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I am confused. Why increasing cin would help xtal_in equals to xtal_out? It would decrease the close loop gain but both the amplitudes would be decreased either. So why not run close loop ac to find out the gain from xi to xout first?