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4#
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發表於 2009-7-10 00:25:48
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VBE=(kT/q)*ln(Is/Io)這個我知道~不過製程裡面有IO嗎?我不知道要帶什麼值進去?
. q- r+ i/ F9 A9 c3 o- m; O, r大大 lx0(XX)就可以畫出Vbe對電壓or電流得值?可以說明詳細一點嗎?以下是參數值
& P% {9 m2 W2 i.MODEL pnp10 PNP ( LEVEL = 1
* E; A# {2 O d! T1 @9 X+ A. c+ BF = 6.35 NF = 1.01 ISE = 2.95E-17
6 \& @0 q* a2 k7 k, }+ NE = 1.9 IS = 2.95E-17 RB = 71 % G" E5 L2 E& O) x
+ IRB = 9.5E-4 RBM = 0.1 RE = 2.35
4 J' H" A4 k. C$ `- Z; L. O+ IKF = 1.95E-3 NKF = 0.549 VAF = 300
$ m, y" e$ {6 d$ k- d& a+ BR = 0.01116 NR = 1 ISC = 2.95E-17
1 @2 f- `+ x u4 d+ Q+ NC = 1.1 RC = 21.08 IKR = 0.087818 2 T! } C3 I0 \) ~/ J
+ VAR = 7.8 TBF1 = 6.7E-3 TBF2 = 8E-6
5 k+ Z4 b/ d* g6 d+ TNE1 = 9E-5 TNF1 = 9.5E-5 TRB1 = 3E-5 8 }4 o6 j) w, a% ]" |
+ TIRB1 = 9E-4 TRM1 = 9.44068E-6 TRE1 = 5E-4 6 A1 I5 T! ^2 `1 P9 h3 G
+ TIKF1 = -3.5E-3 TVAF1 = -9E-4 TBR1 = -7E-4 4 r! Q2 v6 }# t5 T: \ u/ s
+ TBR2 = 9.5E-6 TNR1 = 9E-5 TNC1 = 1.50731E-3
0 Y0 k V7 {! z. E, H. p+ XTB = 0 XTI = 3 TRC1 = 0
. \; K- ]( M' S$ B' ^) {+ TIKR1 = -3.9E-3 EG = 1.18 CJE = 1.55101E-13
2 h4 l/ a' X8 ]/ g" f6 [0 h+ VJE = 1.23623 MJE = 0.662557 FC = 0.5 3 x/ I" f* X4 y1 h
+ CJC = 3.131405E-14 VJC = 0.552774 MJC = 0.32993 2 i5 u* g0 l. M, x5 d5 U- u
+ TLEVC = 1 CTE = 4.87874E-4 CTC = 2.63294E-3
3 c: ` v! P+ b' E7 c. e+ TVJE = 2.16319E-3 TVJC = 2.955E-3 TREF = 25 b0 k; N2 Z: h, a! ^$ H1 E: A |, P
+ SUBS = 1 TLEV = 0 )
& V2 @5 G# H7 c! `. l
# Q9 C% w: B! E0 `- A[ 本帖最後由 leaf1989 於 2009-7-10 12:27 AM 編輯 ] |
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