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發表於 2008-10-7 19:33:22
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LIBRARY ieee; . q3 G2 G6 }7 {' R# ?! j; u
USE ieee.std_logic_1164.all; USE ieee.std_logic_unsigned.all;% m0 h3 N" m0 B
ENTITY counter_60_seg_v IS' Q8 |9 W3 C+ I% U
PORT(Clrn,Load,Ena,Clk : IN STD_LOGIC;
+ E( }1 C" A9 J n0 x- W6 d D0,D1 : IN STD_LOGIC_VECTOR(3 downto 0);
* u" _$ I% K1 L: C Q0,Q1 : OUT STD_LOGIC_VECTOR(3 downto 0);
/ O! k1 {% I# ^0 l% Y8 J8 P, W Co : OUT STD_LOGIC);
" y, f" W6 @9 H) ?9 TEND counter_60_seg_v;' v/ h8 [$ M" @2 K1 i4 x( H
ARCHITECTURE arc OF counter_60_seg_v IS
& v9 O# ?: Y2 Z4 E# |6 Z BEGIN2 b% g& h( |3 K
PROCESS (Clk)& t3 ?$ ?8 h6 N/ z7 L' h$ U
VARIABLE imper0,imper1 :STD_LOGIC_VECTOR(3 downto 0);
* ~& a/ `9 X: g4 Q) K BEGIN
8 d. A. Y p2 P4 D4 Z IF Clrn='0' THEN imper1 := "0000"; imper0 := "0000";
. T( A$ l8 s) r; r" |$ a ELSE IF (Clk'event AND Clk='1') THEN( C( P+ m% K9 e
IF Load='0' THEN imper0 :=D0; imper1:=D1;
3 F! E+ R# r# ^7 }0 e) e ELSIF Ena='1' THEN) A0 L6 `' g* `
IF imper0="1000" AND imper1="0101" THEN $ P. l( C1 V1 h6 W; b5 Y+ _. E
imper0:="1001";/ Y2 [5 j& S* D2 c3 p+ D; e( H
ELSIF imper0<"1001" THEN imper0 := imper0+1;: d" g' y7 k0 d/ \ b J. y
ELSE imper0:="0000";% h c# Y' D0 d p' a7 w
IF imper1<"0101" THEN imper1:= imper1+1;9 I m, {9 ^5 g! b/ H' R
ELSE imper1:="0000"; & T( o, @# Y$ u" S0 y k+ H K
END IF;- W( Z1 S$ ~- M7 T2 I) x9 F. m
END IF;
* k. D0 Z2 e( ~: k# l( J* `: n; a END IF;
. I4 J4 ~4 V9 L0 i1 ~ END IF;
) K3 T7 f% t! B' e# X/ {# n3 ] END IF;# W5 x( \ L. e; \5 a1 O( _
Co<=imper0(0)and imper0(3)and imper1(0)and imper1(2)and Ena;
1 T) g! u2 t% N9 i5 R- b% @ Q0 <= imper0; Q1 <= imper1; ; T& m6 H) B: i( U# G8 j8 Y
END PROCESS ;6 P( }$ K' b: T1 `, p# ?
END arc;
6 l' j K$ p* K3 m, n" r/ n0 g, \
& l% x9 Z' F" r$ j+ E3 G# k這個是60模計數器設計/ U Y. e& Z% z% ^5 S
要怎弄成倒數60?
+ t7 {4 Z6 t6 c3 `2 ^9 X/ o0 T( J A" ]有人會用成倒數60秒先幫忙吧) P2 |3 Q$ p" R$ |
請問一下我會用到幾對幾的多工器啊 |
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