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發表於 2009-7-10 00:25:48
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VBE=(kT/q)*ln(Is/Io)這個我知道~不過製程裡面有IO嗎?我不知道要帶什麼值進去?' d3 A# z/ ]$ N2 W6 j# J
大大 lx0(XX)就可以畫出Vbe對電壓or電流得值?可以說明詳細一點嗎?以下是參數值. x0 F9 G: o! B6 u, c; k3 O
.MODEL pnp10 PNP ( LEVEL = 1 7 J- S* ~! z! f$ S
+ BF = 6.35 NF = 1.01 ISE = 2.95E-17 . I' K) U! r2 m) e' ?5 x' t+ @8 |0 A( V' l
+ NE = 1.9 IS = 2.95E-17 RB = 71
: c y, A" K) R, \+ IRB = 9.5E-4 RBM = 0.1 RE = 2.35
s' A+ l! L( c. b0 k+ IKF = 1.95E-3 NKF = 0.549 VAF = 300 4 P$ |! \) k4 y. a; p# p$ x
+ BR = 0.01116 NR = 1 ISC = 2.95E-17 ) L. V) d4 \, {/ R
+ NC = 1.1 RC = 21.08 IKR = 0.087818
+ M& H* v$ p! K: Z. I8 E+ s( I+ VAR = 7.8 TBF1 = 6.7E-3 TBF2 = 8E-6 . S1 B4 L0 F/ C; ]
+ TNE1 = 9E-5 TNF1 = 9.5E-5 TRB1 = 3E-5
2 w- u% b' Y) `9 g" Z7 j3 w* n* c+ TIRB1 = 9E-4 TRM1 = 9.44068E-6 TRE1 = 5E-4 " t3 S$ k2 ^) Q8 t# _" R
+ TIKF1 = -3.5E-3 TVAF1 = -9E-4 TBR1 = -7E-4
6 ?! Z$ S1 c- F! M; g' w2 a+ TBR2 = 9.5E-6 TNR1 = 9E-5 TNC1 = 1.50731E-3 1 I ?) Q+ J8 b
+ XTB = 0 XTI = 3 TRC1 = 0
3 }5 Z- s( s7 U# I+ TIKR1 = -3.9E-3 EG = 1.18 CJE = 1.55101E-13
3 n# f/ N9 B H9 g, I+ VJE = 1.23623 MJE = 0.662557 FC = 0.5 + h4 C4 J/ \" Z5 f& V
+ CJC = 3.131405E-14 VJC = 0.552774 MJC = 0.32993 3 S( ] X* [1 X2 Y6 ~. R( D C
+ TLEVC = 1 CTE = 4.87874E-4 CTC = 2.63294E-3
/ B' X' H! d1 s+ TVJE = 2.16319E-3 TVJC = 2.955E-3 TREF = 25 % q k, r2 f) K p8 P9 l
+ SUBS = 1 TLEV = 0 )# {/ c Y$ e0 O* ]4 P: F) I
8 ^+ C( T' Y3 b[ 本帖最後由 leaf1989 於 2009-7-10 12:27 AM 編輯 ] |
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