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發表於 2009-7-10 00:25:48
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VBE=(kT/q)*ln(Is/Io)這個我知道~不過製程裡面有IO嗎?我不知道要帶什麼值進去?
, q$ A' g Z1 b+ ~大大 lx0(XX)就可以畫出Vbe對電壓or電流得值?可以說明詳細一點嗎?以下是參數值* U5 c( z& i% c8 t( V- u; O9 d
.MODEL pnp10 PNP ( LEVEL = 1
1 V9 P, |) }( _0 d' a4 Z3 _5 L+ BF = 6.35 NF = 1.01 ISE = 2.95E-17 + T9 d$ C; R* q% c
+ NE = 1.9 IS = 2.95E-17 RB = 71 3 l4 C& H. D( W* v' B
+ IRB = 9.5E-4 RBM = 0.1 RE = 2.35 8 K, S- K1 N* x8 Y( a" _
+ IKF = 1.95E-3 NKF = 0.549 VAF = 300
! ?( d, ? I) k! t. ^+ BR = 0.01116 NR = 1 ISC = 2.95E-17
o6 @* ^# F% a9 f2 r+ NC = 1.1 RC = 21.08 IKR = 0.087818 & \, C6 ^% [5 b7 U- g, X5 p: y
+ VAR = 7.8 TBF1 = 6.7E-3 TBF2 = 8E-6
5 M* t+ a, p! }5 r+ TNE1 = 9E-5 TNF1 = 9.5E-5 TRB1 = 3E-5 ' J3 ?; g# k; j" b" k& J9 d
+ TIRB1 = 9E-4 TRM1 = 9.44068E-6 TRE1 = 5E-4
4 S+ f/ ?5 C! i- L5 A+ TIKF1 = -3.5E-3 TVAF1 = -9E-4 TBR1 = -7E-4 b, E% H/ U3 A
+ TBR2 = 9.5E-6 TNR1 = 9E-5 TNC1 = 1.50731E-3 ( F( N$ c3 ?4 `
+ XTB = 0 XTI = 3 TRC1 = 0 / z( b( \2 S( j4 A; j# l" R( ^5 `
+ TIKR1 = -3.9E-3 EG = 1.18 CJE = 1.55101E-13 4 M& h& T c6 S8 ?* e) P
+ VJE = 1.23623 MJE = 0.662557 FC = 0.5
; \' Q: Y/ {& D6 |; `0 y, n! A+ CJC = 3.131405E-14 VJC = 0.552774 MJC = 0.32993 ! o5 v9 R; ~ q+ p- ]' M
+ TLEVC = 1 CTE = 4.87874E-4 CTC = 2.63294E-3
4 J) C( L2 e$ X! O# s+ TVJE = 2.16319E-3 TVJC = 2.955E-3 TREF = 25 9 {3 |/ Z5 X6 H1 X0 ?. U
+ SUBS = 1 TLEV = 0 )
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, x. X% R" G# m2 Z4 Q[ 本帖最後由 leaf1989 於 2009-7-10 12:27 AM 編輯 ] |
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