VCO V-F曲線量測問題

a016004

目前在研究LC VCO，從前人所提出用hspice 量測V-F曲線的方法得知利用
.meas tran period trig V(out1) val=0.9 rise=50 targ V(out1) val=0.9 rise=100
* K/ i8 J8 D; K2 W+ b$ \) J3 {$ ~! o.meas tran f param='50/period'
7 s* K4 N! ]& h以及搭配.tran 0.1n 100n sweep in 0 1.8 0.1之語法

2 @0 c% J' `4 z1 x+ y但我照上敘的方法，結果量測的每一點電壓的變化出來的頻率都一樣
不知是我那邊的語法沒有打好
我的可變電容輸入(in)是用pwl指令，從0v掃到1.8v
( ?( z- u. C- Q# n7 ]3 Z請各位前輩可給點意見...謝謝
以下是我的spice code
) F& s% \# x: ~
.PARAM
.GLOBAL gnd
+        vdd
.SUBCKT vco_nm in out1 out2 vbaise
& ?8 Y7 y) O" }5 z) P: N+ kMM0 out2 out1 vdd vdd pch W=5u L=180n M=80
* w+ _7 b1 g3 u1 ~% [) EMM1 out1 out2 vdd vdd pch W=5u L=180n M=80
2 s. n+ m: [7 v) rMM5 in out2 in vdd pch W=5u L=180.00n M=150
: h+ [* V: P" n' ~. EMM4 in out1 in vdd pch W=5u L=180.00n M=100
MM6 net32 vbaise gnd gnd nch W=5u L=180n M=60
. P, X1 _6 T: o& o7 b/ i& O3 l8 AMM2 out2 out1 net32 net32 nch W=5u L=180n M=60
, y" `6 C' l& ~: H8 j8 Y1 ?MM3 out1 out2 net32 net32 nch W=5u L=180n M=60
LL0 out1 out2 0.8n $[LP]
4 d7 N. ]& G1 @* T" }* g.ENDS

x1 in out1 out2 vbaise vco_nm
v1 gnd 0 dc 0v
. _9 O$ d6 ?6 U5 c! `% M7 E# G3 mv2 vdd 0 dc 1.8v
5 S3 F0 L( t, `v3 in 0 pwl 0n 0v 100n 1.8v
v4 vbaise 0 dc 1.8v

c1 out1 gnd 0.5p
c2 out2 gnd 0.5p
) g+ r0 O2 ?, t4 c7 T6 q, u8 o& ?.meas tran period trig V(out1) val=0.9 rise=50 targ V(out1) val=0.9 rise=100
.meas tran f param='50/period'
: g4 E5 q2 ~2 p* ?) H$ j- T
.tran 0.1n 100n sweep in 0 1.8 0.1
.option post
.end

poseidonpid

.tran 0.1n 100n sweep in 0 1.8 0.1
這一行不會動作，當然會看到的都一樣啊~
改成
v3 in 0 0
.tran 0.1n 100n sweep v3 0 1.8 0.1
應該就可以了

a016004

我有照樓上的前輩所說的下去做
但跑出來量測不到波形
輸出波形如下

poseidonpid

.PARAM
/ f+ W: M& r: I: M4 T8 i, Y.GLOBAL gnd
: D0 v" b, m0 N+        vdd
2 T, Q. H" v" W.SUBCKT vco_nm in out1 out2 vbaise
9 W& M( G# C) J0 [- S+ g. SMM0 out2 out1 vdd vdd pch W=5u L=180n M=80
MM1 out1 out2 vdd vdd pch W=5u L=180n M=80
MM5 in out2 in vdd pch W=5u L=180.00n M=150
MM4 in out1 in vdd pch W=5u L=180.00n M=100
- e' {8 W$ y" x4 J$ k  bMM6 net32 vbaise gnd gnd nch W=5u L=180n M=60
3 |: S. q' w* L( W7 z7 [MM2 out2 out1 net32 net32 nch W=5u L=180n M=60
3 @9 N! w. {6 g5 }& N) UMM3 out1 out2 net32 net32 nch W=5u L=180n M=60
LL0 out1 out2 0.8n $[LP]
+ \. F( z+ R6 V8 e) G, y2 [.ENDS
/ J; v2 c6 Z! T8 u
. K( g1 I5 A7 o* ~" ox1 in out1 out2 vbaise vco_nm
v1 gnd 0 dc 0v
v2 vdd 0 dc 1.8v
% r! Q0 X% r+ D! K8 }: Av3 in 0 pwl 0n 0v 100n test
v4 vbaise 0 dc 1.8v
: f) [8 ^2 ?  r* f* g/ r8 I: E
.param test=1.8
  ~) s( {8 w6 E

c1 out1 gnd 0.5p
% f1 b, e8 D+ U3 Jc2 out2 gnd 0.5p
, R  i) r' A9 O* ?/ s.meas tran period trig V(out1) val=0.9 rise=50 targ V(out1) val=0.9

0 t( H  i5 F1 o, v( U( {5 Drise=100
.meas tran f param='50/period'

.tran 0.1n 100n sweep test 0 1.8 0.1
) O( j+ _. N* F8 N0 {4 E& X.option post
.end

這樣就可以了
我有跑過模擬了~
可以看到波形了~
4 H: T; ^0 ^5 [& o  H1 {( @6 Y只是你的meas 指令好像有問題就是了~

deltachen

謝謝大大的分享~知識因分享而壯大！

k9966809

又學習到一課 謝謝大大的分享

becka0704

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