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各位先進們,老師最近派了一個鍵盤掃描題目給我們寫,硬體架構和老師發的一些資料都在附件中,我有寫出來兩個程式,一個是用Mealy狀態機防彈跳和看書說故事的寫法,不過我很討厭Mealy狀態機和看書說故事,所以我又寫了第二個寫法,用旗標交握以及計數器防彈跳,因為班上沒人寫出來,所以才在這裡發帖,主要想看先進們的邏輯寫法,以下是我的程式,寫的邏輯很爛可以噹我沒關係,呵呵...因為小弟弟剛升會員,所以只有1RDB,希望先進們見諒.
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Library ieee;4 m' ^. ]; A* _& B
Use ieee.std_logic_1164.all;
" a% m$ j# y; C, y$ k7 b( z! oUse ieee.std_logic_unsigned.all;! z% R5 G6 _0 ~
+ V# C s. R& s, s# Q9 aEntity Keyboard_scanning_2 is
/ L, N1 ?$ l4 n1 {* fPort(
) t6 ` `9 P9 S5 E8 ^ M clk,c1,c2,p_21 : in std_logic;5 B* K; j5 g3 ^
kbi : in std_logic_vector(2 downto 0);( m' D' J, Y, V$ ]9 B0 e
lt,p_20,p_6 : out std_logic;6 S# o8 z% N q$ ]: [5 l1 }
kscano,key : out std_logic_vector(3 downto 0));
) W$ l3 f. V1 Z `end Keyboard_scanning_2;5 u |1 Y) n$ z }. t! ~8 v
: {8 p C5 Z2 eArchitecture K_S of Keyboard_scanning_2 is
" D, z8 Z: M9 |# x' Psignal x0,x1,x2,x3,ena,l_p,d_b,count : std_logic;; Y9 P8 O2 w( Q0 H1 w) F9 `8 B
signal D : std_logic_vector(1 downto 0);6 \: C+ ~! d! I/ O& G
signal ks1,kok : boolean;5 ]$ `: x" H7 d) D
Begin S: @( X1 N* _- b, ?9 v4 X6 }5 P
lt<=c1 nor c2;. R. j" \! F$ S [
0 u7 T6 n8 k$ f1 R% H; l. [freqp rocess(clk)
; Z$ F" [( N# c9 ?" avariable ff : std_logic_vector(16 downto 0); $ D5 s1 q1 v# I" G
Begin
: I' m5 c4 J# v if (clk'event and clk='1') then
7 I( j9 T1 y$ I3 I' M1 w) L$ c* Y ff:=ff+1;
$ j; X" R0 k5 P( u# L end if;, x2 k" l0 F1 Y) r* c; F
l_p<=ff(12); / \" l. ~8 c+ L1 A( ], d8 G; I
d_b<=ff(13); / |5 d# u1 B4 F7 ]0 r1 h0 u
count<=ff(15); 9 H5 X/ D+ \( r7 w
end process freqp;/ K) U/ ]: z0 \/ H! }3 B& L2 k
`9 ~2 K3 P& p. kdeb rocess(d_b)
1 Z- u+ A6 @, Yvariable c : std_logic_vector(1 downto 0);" ?, {1 x* `# S& u
Begin
! N0 c( h5 w' c4 Y if (d_b'event and d_b='1') then+ X( ?/ Z2 Q$ q% w9 i6 Y% c
if (kbi(2) or kbi(1)or kbi(0))='1' then1 C* o2 M6 b9 c G+ ?8 ?
if c="11" then5 g, X0 p; B, e1 ]
ena<='1';/ }9 M/ a/ X) L6 H! G% B
x2<=kbi(1);# k. _$ u4 e/ X* k- t6 c
x3<=kbi(0);
6 i8 \1 p% f0 h: q R; S" D kok<=false;/ |9 a0 z% p: {' D
else ; a. v7 b n6 U" E) x
c:=c+1;$ e& o3 v2 D2 Y1 a
end if;
. Z- A2 [8 f+ N4 ] elsif (kbi(2) or kbi(1)or kbi(0))='0' then2 A2 F% q& k( f% P C
ena<='0';
9 f5 @0 ` b0 D6 K2 |1 n% p; M kok<=true;* {; D. C E4 E% Z0 W/ d* Z
c:="00";
, e! @6 R9 R6 z1 {; r end if;
! O: q8 O- c6 i1 s" G3 D end if;
* s2 T% t) S& T- A- z3 L! s: @9 jend process deb;: ]- X U" B$ v# u0 ]$ P7 p
8 c& ]% v. V$ ~4 Z3 E/ r% T, v) d
counter_scan rocess(count)
' `8 ?) w0 M3 E* gBegin
5 y; r a6 p- @8 x! x if (count'event and count='1') then6 H4 c# [+ ?2 r' Q* }# R
if ena='1' then
* o8 \( g" }9 V1 | x1<=D(1);
- ]% x [& f3 b7 q x0<=D(0);: n+ x. b+ C1 O1 ?; o
else
, N8 S8 t3 H0 o, ?6 i if D="11" then+ L; a: _( D y/ K$ l: m
D<="00";
8 m5 Q5 C0 l2 R9 ]( I! A* x else
6 p' H4 ]8 Q# r! ~( B8 w, A D<=D+1;
) l" F& T& J% q, h. b3 e3 X+ g end if;, P$ J) ?+ \. b# y' H& h
end if;2 j/ @7 \7 m k1 E; b) s
end if;) }+ W. e1 B- i- J! ?/ e
case D is: k' n' w$ A+ |
when "00"=>
1 B# U8 n8 J. j3 u2 e, W% o kscano<="0001";
K$ C5 e0 f4 D/ @) j- | when "01"=>
) O4 U ~! B5 ~" B& ~ kscano<="0010"; # ]6 F' e" e- V
when "10"=>
6 ^8 w2 d* U8 |7 U* ? kscano<="0100"; 2 B1 H- Y) e5 z ]+ K& @* {
when "11"=>
& h2 ]) Q6 b2 u- O kscano<="1000";0 D+ C2 \' i$ W7 \
when others=>null; M2 _1 x0 m0 k
end case;
6 i( b6 N9 d Q3 n7 }9 send process counter_scan;
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ld_pls rocess(l_p)
, h/ v. ~7 l- i0 G3 G- \* Z9 yBegin
9 S* S/ e: u4 {9 {: }6 ` if (l_p'event and l_p='1') then0 S8 T1 o4 K7 \& H
if ena='1' then
1 ?2 ]9 m& M- k, j* V8 b- b+ y" n if ks1 then
9 N r% O; U( r b- E% { p_6<='1';& u7 ^7 }& w$ D2 s. _7 n
p_20<='0';
' E' B( K: i4 g; i; D7 E% p ks1<=false;0 N& ^/ g: {$ N- E5 w
elsif ks1=false then
3 S, x) D% X. ^% F p_6<='0'; ) W: a( X6 F! O4 s0 E9 p
if p_21='1' then# G8 M' {& Q, @8 B
p_20<='1';
8 Q; h- M+ `) ?. a3 v key(3)<=x3;
6 \6 O% d8 A, o4 c/ a key(2)<=x2;
9 D7 G4 U* ~% K$ R key(1)<=x1;
; K# e0 p9 H3 J key(0)<=x0;
; a: M8 M) j1 }" M0 X1 A else
! B2 w* Z( c% M1 O" B p_20<='0';# s$ g7 j$ j) m/ t# q
end if;# p" H O$ Y4 w; E
end if;" U) s7 e4 Q7 a' H, ^
elsif kok then
) |, a- Z3 r8 h) W! q( n ks1<=true;
/ p" V: W# v6 }2 d8 ] end if;) S3 P: M+ g* j
end if;+ t: Z: S/ o* S7 O. {
end process ld_pls;
/ A) b1 T' N$ x2 m4 i3 pend K_S; |
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