VCO V-F曲線量測問題

a016004

目前在研究LC VCO，從前人所提出用hspice 量測V-F曲線的方法得知利用
# D' z5 p/ b, V+ Y0 p.meas tran period trig V(out1) val=0.9 rise=50 targ V(out1) val=0.9 rise=100
  F2 P4 q: M4 ~6 u7 ~* b.meas tran f param='50/period'
1 D( t& Z0 s# l2 h* D0 g0 B以及搭配.tran 0.1n 100n sweep in 0 1.8 0.1之語法

6 W7 i% W* M3 h但我照上敘的方法，結果量測的每一點電壓的變化出來的頻率都一樣
& h3 D. w8 o( O6 @; T  e- l; i不知是我那邊的語法沒有打好
8 `+ s1 w/ f3 {! X我的可變電容輸入(in)是用pwl指令，從0v掃到1.8v
請各位前輩可給點意見...謝謝
8 L& Q( ^$ T5 X. c9 S1 |以下是我的spice code

.PARAM
+ {7 k9 `  z3 b.GLOBAL gnd
9 Q% E5 l/ i) S+        vdd
" r2 [; C+ L7 m/ A" W.SUBCKT vco_nm in out1 out2 vbaise
MM0 out2 out1 vdd vdd pch W=5u L=180n M=80
MM1 out1 out2 vdd vdd pch W=5u L=180n M=80
& u! l7 p+ A* ]" a* KMM5 in out2 in vdd pch W=5u L=180.00n M=150
MM4 in out1 in vdd pch W=5u L=180.00n M=100
MM6 net32 vbaise gnd gnd nch W=5u L=180n M=60
MM2 out2 out1 net32 net32 nch W=5u L=180n M=60
MM3 out1 out2 net32 net32 nch W=5u L=180n M=60
4 Q* i: B# c) v- {LL0 out1 out2 0.8n $[LP]
.ENDS
% Z* u4 O; H9 X; `1 G
x1 in out1 out2 vbaise vco_nm
% i' G1 C9 g# A3 l7 C. F, `! p8 \v1 gnd 0 dc 0v
v2 vdd 0 dc 1.8v
- I. [1 j& |7 d7 Ov3 in 0 pwl 0n 0v 100n 1.8v
v4 vbaise 0 dc 1.8v
! J# x4 p. }- N: @
) U5 o' C1 l, x, v5 z) N3 G: bc1 out1 gnd 0.5p
c2 out2 gnd 0.5p
) V- n& Q( H6 k9 q4 b0 |.meas tran period trig V(out1) val=0.9 rise=50 targ V(out1) val=0.9 rise=100
.meas tran f param='50/period'

.tran 0.1n 100n sweep in 0 1.8 0.1
.option post
' v: L/ \( G7 `.end

becka0704

感謝分享！

k9966809

又學習到一課 謝謝大大的分享

deltachen

謝謝大大的分享~知識因分享而壯大！

poseidonpid

.PARAM
" ?  j5 ]7 j( Z/ o+ }6 p.GLOBAL gnd
+        vdd
.SUBCKT vco_nm in out1 out2 vbaise
+ |% c! X8 x2 g4 v5 Q$ lMM0 out2 out1 vdd vdd pch W=5u L=180n M=80
" Q) b0 y7 y$ ?; U* Z2 |3 V$ SMM1 out1 out2 vdd vdd pch W=5u L=180n M=80
5 j# L  p" X5 k6 e* m2 u2 FMM5 in out2 in vdd pch W=5u L=180.00n M=150
MM4 in out1 in vdd pch W=5u L=180.00n M=100
MM6 net32 vbaise gnd gnd nch W=5u L=180n M=60
) Y3 a  m' t. d% l5 gMM2 out2 out1 net32 net32 nch W=5u L=180n M=60
MM3 out1 out2 net32 net32 nch W=5u L=180n M=60
9 d5 N5 {+ d" Q$ F5 \: FLL0 out1 out2 0.8n $[LP]
.ENDS
9 t) o7 X- U( [  ?  }: e$ u
" j' ]! o" c8 j. K( hx1 in out1 out2 vbaise vco_nm
; q5 w2 W6 _: c! M0 e6 Sv1 gnd 0 dc 0v
v2 vdd 0 dc 1.8v
v3 in 0 pwl 0n 0v 100n test
' k& w( l0 {/ E" W3 K9 _v4 vbaise 0 dc 1.8v
% H* l  o1 \3 N% T
, y' ?& t- b- c; {- \.param test=1.8

# b! u* e" X# k) X9 r* Q
c1 out1 gnd 0.5p
c2 out2 gnd 0.5p
.meas tran period trig V(out1) val=0.9 rise=50 targ V(out1) val=0.9
) V- o1 c. _* W5 S
# I/ N8 l2 }$ b: L( S! l, Grise=100
! ?9 E, t3 f6 {- c: P.meas tran f param='50/period'
0 `' y3 q( b! b0 O# @) g3 U+ Y; i, O' M6 P
. ?" s3 Y6 }7 [; P  l$ D9 V; }0 p.tran 0.1n 100n sweep test 0 1.8 0.1
+ B* J$ F  y& U) a. l0 s.option post
.end

% r; t  R1 U# ?! a0 ?' E( L& E$ \' Z這樣就可以了
8 m0 b! C2 X, ^6 M) h7 Q* J8 Z我有跑過模擬了~
9 ~  Y% k' u! C+ p% j$ a$ ?0 B可以看到波形了~
! N* n5 F# O/ _. M只是你的meas 指令好像有問題就是了~

a016004

我有照樓上的前輩所說的下去做
但跑出來量測不到波形
輸出波形如下

poseidonpid

.tran 0.1n 100n sweep in 0 1.8 0.1
這一行不會動作，當然會看到的都一樣啊~
* a2 h# W! K0 e# M改成
0 O% v) ?) y2 ]v3 in 0 0
7 Q1 H- J& [+ A5 v" \, e.tran 0.1n 100n sweep v3 0 1.8 0.1
! T9 ]+ S, ^0 n8 M9 v應該就可以了