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各位先進們,老師最近派了一個鍵盤掃描題目給我們寫,硬體架構和老師發的一些資料都在附件中,我有寫出來兩個程式,一個是用Mealy狀態機防彈跳和看書說故事的寫法,不過我很討厭Mealy狀態機和看書說故事,所以我又寫了第二個寫法,用旗標交握以及計數器防彈跳,因為班上沒人寫出來,所以才在這裡發帖,主要想看先進們的邏輯寫法,以下是我的程式,寫的邏輯很爛可以噹我沒關係,呵呵...因為小弟弟剛升會員,所以只有1RDB,希望先進們見諒.
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$ ]6 o/ N/ o. ?/ T8 }# Y: k& a5 |' ALibrary ieee;4 \. {2 i; ]) O: e2 A- y
Use ieee.std_logic_1164.all;: d# n& u3 H5 b+ _" R8 E' E9 ~' F
Use ieee.std_logic_unsigned.all;4 j( d* N3 T; ]0 P8 i) A
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Entity Keyboard_scanning_2 is
2 ~, [! `! V" v# i: ?! o/ UPort(
2 o# G; w3 ?5 u T clk,c1,c2,p_21 : in std_logic;: N+ L$ g; ?5 g
kbi : in std_logic_vector(2 downto 0);' W+ B7 h# v# B+ A# C- G
lt,p_20,p_6 : out std_logic;
% e* h# `2 d4 F0 C kscano,key : out std_logic_vector(3 downto 0));
* Y0 z8 w% y( I+ S9 { Qend Keyboard_scanning_2;4 h7 l( M9 L; O# r- [
$ w e$ i2 ^ `/ s% hArchitecture K_S of Keyboard_scanning_2 is' |& C3 R& f2 K! B" C$ I
signal x0,x1,x2,x3,ena,l_p,d_b,count : std_logic;* \: |0 Z: K' C; |0 t* b3 m! K
signal D : std_logic_vector(1 downto 0);
( m& T6 J( G' p. _signal ks1,kok : boolean;4 F4 T5 B7 \8 a8 R9 u# O
Begin
9 K! ?- {/ u0 B% a$ U( Xlt<=c1 nor c2;2 i; @3 v- j' B, E& ?) l
$ o1 V; V3 q$ K8 i3 e1 x0 c, Dfreqp rocess(clk) : ^3 k0 B, \' i
variable ff : std_logic_vector(16 downto 0);
* V* Z1 B/ U4 [2 _Begin
( Q% l- N1 j* \ if (clk'event and clk='1') then7 F& W/ O8 J) s7 k& s3 C
ff:=ff+1;; Y# q2 M$ P9 v* B, a, ?/ B
end if;
5 ]+ T% \; M* ^- t l_p<=ff(12); , V3 m4 b3 H8 F5 e# _9 k
d_b<=ff(13);
1 y: F) h- B: u1 X2 [' w. L count<=ff(15); 6 I& f& _: d5 \; G1 k, K3 F. h) }9 F1 r
end process freqp; E% R% U6 Y# I. w2 u9 {
+ H9 B% Q2 M" Y; Jdeb rocess(d_b)
# z( N0 A" S. O( D7 V# `variable c : std_logic_vector(1 downto 0);* U" I. N( O- L% g6 C
Begin
; t- P* H) C( {$ C if (d_b'event and d_b='1') then$ T* }4 y% O: B% U
if (kbi(2) or kbi(1)or kbi(0))='1' then
( x$ V' R6 I' m5 c! J! U8 O if c="11" then; Q) }" S7 H; P8 X( L5 v& ~" R+ q
ena<='1';
3 x( m2 l' M0 {% A x2<=kbi(1);, u# T& J/ A5 m3 M* z
x3<=kbi(0);
7 H+ ^$ h0 y. x. a kok<=false;
' {! o% Z% r- `# V$ J7 H2 _ else
; p% Z1 W2 N$ G _! I3 g/ O# C c:=c+1;
0 ?6 M4 J7 `+ u end if;9 V9 l( G5 X5 g! s
elsif (kbi(2) or kbi(1)or kbi(0))='0' then Z) a4 L$ K+ h4 \, h0 d* c
ena<='0';! A# ^8 i6 _& H$ p6 c+ q# i' p: v
kok<=true;
4 f8 x9 z! _* f0 H+ N c:="00";
2 i" b, j- o) j: R0 g" b end if; 5 |7 d f0 T' {* i A
end if;/ q( G$ Q5 w; T! j0 T& V
end process deb;
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counter_scan rocess(count)
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if (count'event and count='1') then9 N: b) @4 Q4 Q" X7 A* o
if ena='1' then& L0 F! U0 }9 }2 Z
x1<=D(1); ]" L$ [- G. ]: W g
x0<=D(0);
' e, n# E+ |( n( R else
5 b& W* Q0 Q2 l% i. Y6 p! C: k if D="11" then
4 f* V2 n: b3 h1 e9 j/ T/ c( w5 o ~+ v D<="00";- W# V+ l5 {. u7 y7 T$ w3 m) t& D
else ( Y) x; n, \; {* y# N5 d4 n7 T
D<=D+1;2 F+ @9 \: P' c) R# V5 E
end if;
/ [2 x/ E& V2 @ q& J9 O, N end if;. |4 W {5 k5 D- D" u7 n; m5 P
end if;
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when "00"=>
) ?$ p9 D8 y; p/ J kscano<="0001";" n: M1 K- a6 S5 H0 g
when "01"=>6 c, }3 ~! f+ L# F! n/ v
kscano<="0010"; " f3 [7 |; Z8 ]
when "10"=>
! j8 j" m( C' e/ o8 N3 c kscano<="0100"; 3 z# W- g* `$ x4 }6 F/ _& p
when "11"=>/ H5 ?) m( J; K7 k
kscano<="1000";
0 k8 G& v% T' U5 {* `& Y when others=>null;+ F% C8 g" t% W7 l
end case;
& R" `; y Z) _+ B" C8 [end process counter_scan; o1 _/ c+ k( P3 x: b
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ld_pls rocess(l_p)
+ q) k- R$ F) z! SBegin
7 D5 G5 u$ U; ^- H if (l_p'event and l_p='1') then
( h2 b- \: l. Q) F8 E2 V5 I2 ?& S0 @ if ena='1' then
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p_6<='1';
$ e$ \, M' H3 q( f! \) o6 J p_20<='0';1 B# q! g c, m* y: p5 `& O
ks1<=false;
- r8 M% b! [: Y( F' O9 _ elsif ks1=false then0 U7 H1 o7 s. ^8 H
p_6<='0'; . T) L! ^1 u1 Z$ ?
if p_21='1' then5 i: I9 I+ `% q. t5 A$ E! s/ m, @
p_20<='1';. Y" z' _) M, \! m: R1 R
key(3)<=x3;
8 D1 h1 \' C- f( ]# S0 _% ] key(2)<=x2;# p8 a E% _8 {- D9 _& l8 ^
key(1)<=x1;# B! p! B& S& z. g9 g
key(0)<=x0;
% a E8 a. p+ V1 H% @" m& v- {1 E1 i else
- B% G- w7 U. w2 T p_20<='0';
' D- u8 D, l, E! W7 e2 M9 m1 P end if;
; B; H& l- P) e/ N end if;
( k7 `( H+ |% O elsif kok then3 ?0 d" g" k! e7 b
ks1<=true; 8 x4 T/ G1 ~( d5 E
end if;9 ^3 Q% |1 t5 |, _( j. E% f* W
end if;+ u, S' u7 b e* W
end process ld_pls;7 ]+ O; W5 }( k. l: C5 o5 J
end K_S; |
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